September 30, 2014
This week’s lecture started with exercises on equivalencies with quantifiers, disjunctions, and conjunctions. Despite having worked on the first assignment this week, I had no idea how to find the answer. The first question was:
P=>Q is equivalent to:
A. ¬P ∨ Q
B. P ∨ ¬Q
C. P ∧ ¬Q
D. P ∧ Q
E. None of the above
I thought of the implication of this quantifier logically, but could not come to a conclusion. As he worked through the answer, it seems like this is less intuitive, and is only clear when the negative of this equation is worked out and compared to the already known equivalency. This exercised reminded me of the brief laws that were mentioned at the end of the previous class. I referenced week 3’s material in the next questions, and was then able to answer the questions. I was at a loss, because Larry had zoomed through the material (despite having a decent amount of time). It seemed like this material was not as important or will be covered in this week’s lecture, so I did not bother looking through these slides.
Looking through some of the theorems, they are very intuitive, but thinking of these formulas in a logical manner every time there was an equivalency question, seemed inefficient. So, I will probably straight off memorize the formulas.
Next thing that came up in class was sort of a fun surprise. Larry introduced it as a “real-life” proof. It was the hanging man paradox. To me, this was totally from left-field. The previous proof was a serious, down-to-Earth math question, but this question was a “neat-test-my-friends’-logic” kind of question. We did not have a lot of time to think this through, but the whole question is very interesting nonetheless, and I just might quiz my friends on it. If I was given the time, I wonder if I would be able to figure it out…
At the end of class, there was a folding exercise. I teamed up with a classmate named Jackie, and tried to work out the problem. Initially, trying to record the up and downs of the paper was very hard, as it kept flopping over, and had to keep the top and bottom consistent as we added more folds. After trying to re-record the folds many times, we started to be more familiar with the patterns. Initially, we looked at the sequences of up and downs. There were no apparent sequences. However, once I thought of the problem logically (i.e. not in patterns, but focusing on what is actually happening to the paper), I had an “ah-ha!” moment. The paper is getting folded onto itself, and so the creases are happening between the previous crease. In addition, if there is a fold on the one side, there must be another fold on the other side that fits in with the fold. So if we start of with our initial sequence, if we space it out, and as long as we can fill in the inbetween of one side, the other will be simple! I had thought it would simply be one UP fold on the other, while the other was DOWN. Happily satisfied with my answer, I waited for Larry’s real answer.
As you know, there is a slight flaw to my answer, as all the creases on one side do not become just one kind of fold. Almost there, but not quite there. Regardless, the exercise was very engaging and enjoyable.
In this week’s tutorial, Grace very graciously answered my “dur” questions. Thanks again!
Until next time,
Maya.